-16(x^2)+64x+175=0

Solution for -16(x^2)+64x+175=0 equation:

-16(x^2)+64x+175=0

a = -16; b = 64; c = +175;
Δ = b2-4ac
Δ = 642-4·(-16)·175
Δ = 15296
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{15296}=\sqrt{64*239}=\sqrt{64}*\sqrt{239}=8\sqrt{239}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(64)-8\sqrt{239}}{2*-16}=\frac{-64-8\sqrt{239}}{-32}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(64)+8\sqrt{239}}{2*-16}=\frac{-64+8\sqrt{239}}{-32}
$